5.3 Dimension
Introduction
One dimension is a line, two dimensions is a plane, three dimensions is the space we live in – everyone has an intuitive sense of this. But how do we define “dimension” rigorously in mathematics?
Dimension is the minimum number of independent directions needed to describe a space. In linear algebra, this number is precisely the number of vectors in a basis.
Here is the remarkable fact: no matter which basis you choose for a given vector space, the number of basis vectors is always the same. This is the theorem that makes dimension a well-defined concept.
Definition of Dimension
The dimension of a vector space $V$ is the number of vectors in any basis for $V$:
\[\dim(V) = \text{(number of vectors in a basis)}\]This number does not depend on which basis you choose.
Special case: The zero space ${\vec{0}}$ has the empty set as its basis, so
\[\dim(\{\vec{0}\}) = 0\]Familiar Examples
$\mathbb{R}^1$ – The Number Line
Basis: ${1}$ (or any single nonzero real number) \(\dim(\mathbb{R}^1) = 1\)
$\mathbb{R}^2$ – The Plane
Basis: ${\hat{e}_1, \hat{e}_2} = {(1,0)^\top, (0,1)^\top}$ \(\dim(\mathbb{R}^2) = 2\)
Another valid basis: ${(1,1)^\top, (1,-1)^\top}$ – these vectors are linearly independent and span $\mathbb{R}^2$, so they form a legitimate basis.
$\mathbb{R}^3$ – Three-Dimensional Space
Basis: ${\hat{e}_1, \hat{e}_2, \hat{e}_3}$ \(\dim(\mathbb{R}^3) = 3\)
Dimension Table
| Space | Example Basis | Dimension |
|---|---|---|
| ${\vec{0}}$ | Empty set $\emptyset$ | $0$ |
| Line through the origin | One vector along the line | $1$ |
| Plane through the origin | Two non-parallel vectors | $2$ |
| $\mathbb{R}^2$ | ${\hat{e}_1, \hat{e}_2}$ | $2$ |
| $\mathbb{R}^3$ | ${\hat{e}_1, \hat{e}_2, \hat{e}_3}$ | $3$ |
| $\mathbb{R}^n$ | ${\hat{e}_1, \ldots, \hat{e}_n}$ | $n$ |
The Dimension Theorem
Theorem: Every basis for a finite-dimensional vector space $V$ contains the same number of vectors.
Without this theorem, the very definition of dimension would be ambiguous. The key idea behind the proof: assuming two bases of different sizes leads to a contradiction.
Corollaries:
- Any set of $\dim(V)$ linearly independent vectors in $V$ is automatically a basis.
- Any set of $\dim(V)$ vectors that spans $V$ is automatically a basis.
Dimension of Subspaces
If $W$ is a subspace of $V$, then
\[\dim(W) \leq \dim(V)\]Equality holds if and only if $W = V$.
Example: Subspaces of $\mathbb{R}^3$:
| Subspace | Geometric Meaning | Dimension |
|---|---|---|
| ${\vec{0}}$ | The origin | $0$ |
| $\text{span}{\vec{v}}$ | Line through the origin | $1$ |
| $\text{span}{\vec{v}_1, \vec{v}_2}$ | Plane through the origin | $2$ |
| $\mathbb{R}^3$ itself | Full 3D space | $3$ |
Extending and Reducing to a Basis
Basis extension theorem: A basis $\mathcal{B}_W$ for a subspace $W$ can always be extended to a basis $\mathcal{B}_V$ for the full space $V$.
Extending a linearly independent set: You can keep adding vectors to a linearly independent set (while preserving independence) until you reach a basis.
Reducing a spanning set: You can keep removing redundant vectors from a spanning set (while preserving the span) until you arrive at a basis.
Intuitive Understanding
Think of dimension as the number of degrees of freedom.
- To specify a point on a line (1D space), you need one number.
- To specify a point on a plane (2D space), you need two numbers.
- To specify a point in $n$-dimensional space, you need $n$ numbers.
Number of basis vectors = number of independent numbers needed to describe the space = dimension.
Key Takeaways
| Concept | Description / Formula |
|---|---|
| Definition of dimension | $\dim(V)$ = number of vectors in a basis |
| Dimension of the zero space | $\dim({\vec{0}}) = 0$ |
| Dimension of $\mathbb{R}^n$ | $\dim(\mathbb{R}^n) = n$ |
| Dimension theorem | Every basis has the same number of vectors |
| Subspace dimension | $\dim(W) \leq \dim(V)$ |
| Intuition | Dimension = number of numbers needed to specify a point in the space |
Next up: Null Space and Column Space – when does the matrix equation $A\vec{x}=\vec{b}$ have a solution?
